How do you simplify the expression $\frac{- 12 x^{- 3} y^{3}}{3 x^{- 5} y^{5}}$ $(-12x^-3y^3)/(3x^-5y^5)$ ?

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How do you simplify the expression $\frac{- 12 x^{- 3} y^{3}}{3 x^{- 5} y^{5}}$ $(-12x^-3y^3)/(3x^-5y^5)$ ?

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Answer 1 · 2016-10-25T13:20:05

$- \frac{4 x^{2}}{y^{2}}$ $-(4x^2)/(y^2)$

Explanation:

Using the $laws of exponents$ $color(blue)"laws of exponents"$

$color(orange)"Reminder " color(red)(bar(ul(|color(white)(2/2)color(black)(a^-mhArr1/a^m)color(white)(2/2)|)))$

$rArr(-12x^-3y^3)/(3x^-5y^5)=(-12)/3xxx^-3/x^-5xxy^3/y^5$

$=-4xxx^(-3-(-5) xx 1/y^(5-3)$

$=-4xx x^2 xx1/y^2$

$=-(4x^2)/y^2$

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How do you simplify the expression $\frac{- 12 x^{- 3} y^{3}}{3 x^{- 5} y^{5}}$ $(-12x^-3y^3)/(3x^-5y^5)$ ?

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How do you simplify the expression (-12x^-3y^3)/(3x^-5y^5)−12x−3y33x−5y5(-12x^-3y^3)/(3x^-5y^5)?

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How do you simplify the expression $\frac{- 12 x^{- 3} y^{3}}{3 x^{- 5} y^{5}}$ $(-12x^-3y^3)/(3x^-5y^5)$ ?