How do you simplify the expression $(4m^4)/(-6m^-2n^5)*(3n^-1)/m^-2$ using the properties?

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Answer 1 · 2017-11-09T17:33:33

$=-(2m^8)/(n^6)$

Some of the laws of indices state:

$x^m xx x^n = x^(m+n)$

$x^-m = 1/x^m" "and" "1/x^-m = x^m$

This means that negative indices can be changed to positive indices.

$(4m^4)/(-6m^-2n^5) xx (3n^-1)/(m^-2)$

$= (4m^4m^2)/(-6n^5) xx (3m^2)/(n)" "larr$ all positive indices

$= (cancel4^2m^4m^2)/(-cancel6^cancel2n^5) xx (cancel3m^2)/(n)$

$=-(2m^8)/(n^6)$

How do you simplify the expression (4m^4)/(-6m^-2n^5)*(3n^-1)/m^-2(4m^4)/(-6m^-2n^5)*(3n^-1)/m^-2 using the properties?