How do you simplify $((x^(1/2)y^-2)/(yx^(7/4)))^4$ ?

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Answer 1 · 2017-08-26T16:22:06

$1/(x^5 y^12)$

$((x^(1/2) y^-2)/(y x^(7/4)))^4$

$((x^(1/2 xx 4) y^(-2 xx 4))/(y^4 x^(7/4 xx 4)))$

$((x^2 y^-8)/(y^4 x^7))$

$x^2 y^-8 div y^4 x^7$

Recall

$a^x xx a^y = a^(x+y)$

$a^x div a^y = a^(x-y)$

$rArr x^(2 - 7) y^(-8 - 4)$

$rArr x^-5 y^-12$

$rArr 1/(x^5 y^12)$

How do you simplify ((x^(1/2)y^-2)/(yx^(7/4)))^4((x^(1/2)y^-2)/(yx^(7/4)))^4?