How do you simplify #(x^2y)/4*(16x)/y#?

Question

1761 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-12-03T04:03:38

#4x^3#

First, multiply the numerator and denominator and group terms using the rules for exponents:

#(16x2x^1y)/(4y)#

#(16x^(2 + 1)y)/(4y)#

#(16x^3y)/(4y)#

Next, separate terms and factor:

#(16/4)x^3(y/y)#

#4*x^3*1#

#4x^3#