How do you simplify #( x^-3 y^ -5 )/z^-2#?

Question

1587 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-09-05T11:06:49

#(z^(2)) / (x^(3) y^(5))#

We have: #(x^(- 3) y^(- 5)) / (z^(- 2))#

Let's express the variables as fractions:

#= ((1) / (x^(3)) cdot (1) / (y^(5))) / ((1) / (z^(2)))#

#= ((1) / (x^(3) y^(5))) / ((1) / (z^(2)))#

#= ((1) / (x^(3) y^(5))) / ((1) / (z^(2))) cdot (z^(2)) / (z^(2))#

#= ((z^(2)) / (x^(3) y^(5))) / (1)#

#= (z^(2)) / (x^(3) y^(5))#