How do you simplify #(x+i)^2-(x-i)^2#?
1 Answer
Jan 15, 2017
Explanation:
Note that in general:
#(a+b)^2 = a^2+2ab+b^2#
#(a-b)^2 = a^2-2ab+b^2#
So:
#(a+b)^2-(a-b)^2 = 4ab#
In our example:
#(x+i)^2-(x-i)^2 = 4ix#
