How do you simplity 6cot2θ−cosθ to trigonometric functions of θ?

1 Answer
Ratnaker Mehta
Jul 6, 2016

3(cotθ−tanθ)−cosθ.

Explanation:

cot2θ=cos(2θ)sin(2θ)=cos2θ−sin2θ2sinθcosθ=12{cos2θcosθsinθ−sin2θsinθcosθ}=12(cotθ−tanθ)

Hence, the Given Exp. =3(cotθ−tanθ)−cosθ.

Related questions
See all questions in Double Angle Identities
Impact of this question
1507 views around the world
You can reuse this answer
Creative Commons License