How do you solve #0.25^x-0.5=2#? Precalculus Properties of Logarithmic Functions Natural Logs 1 Answer EZ as pi Jul 15, 2016 #x = -0.661 # Explanation: #0.25^x = 2+0.5 = 2.5# #xlog 0.25 = log2.5" take log of both sides"# #x = (log2.5)/(log0.25)# #x = -0.661 " 3 dp"# Answer link Related questions What is the natural log of e? What is the natural log of 2? How do I do natural logs on a TI-83? How do I find the natural log of a fraction? What is the natural log of 1? What is the natural log of infinity? Can I find the natural log of a negative number? How do I find a natural log without a calculator? How do I find the natural log of a given number by using a calculator? How do I do natural logs on a TI-84? See all questions in Natural Logs Impact of this question 3492 views around the world You can reuse this answer Creative Commons License