How do you solve #1/2x+5/6=7/12#?

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Answer 1 · 2017-04-12T16:56:16

If there are fractions in an equation, you can get rid of the denominators by multiplying though by the LCM of the denominators:

#1/2x +5/6 = 7/12" "larr LCM = 12#

#color(red)(cancel12^6xx1x)/cancel2 +color(red)(cancel12^2xx5)/cancel6 = color(red)(cancel12xx7)/cancel12" "larr# cancel denominators

#6x +10 = 7#

#" "6x = 7-10#

#" "6x = -3#

#" "x = -1/2#