Question

How do you solve `1/(3m)+(6m-9)/(3m)=(3m-3)/(4m)`?

Answer 1

`m=0 " "Or" "m=23/15`

Explanation:

`1/(3m)+(6m-9)/(3m) = (3m-3)/(4m)`
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`rArr(1+6m-9)/(3m)=(3m-3)/(4m)`
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`rArr(-8+6m)/(3m)=(3m-3)/(4m)`
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`rArrcolor(blue)((-8+6m)xx4m = (3m-3)xx3m)`
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`rArr-32m + 24m^2 = 9m^2-9m`
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`rArr-32m + 24m^2 - 9m^2+9m=0`
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`rArr15m^2-23m=0`
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`rArrm(15m-23)=0`
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`m=0`
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Or
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`15m - 23 =0rArr15m = 23rArrm=23/15`