How do you solve #1/4(x-3) = 2#?

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Answer 1 · 2016-03-15T14:26:18

#x=11#

#color(blue)(1/4(x-3)=2#

#rarr(x-3)/4=2#

Multiply both sides by #4#

#rarr(x-3)/cancel4*cancel4=2*4#

#rarrx-3=8#

Add #3# both sides

#rarrx-3+3=8+3#

#rArrcolor(green)(x=11#