Question

How do you solve `1/(6a) + 1/(3a^2) = 1/(3a)` and find any extraneous solutions?

Answer 1

`a/(6a^2) + 2/(6a^2) =(2a)/(6a^2)`

`a+ 2 = 2a`

`2 = 2a - a`

`a = 2`

It's worth noting that `a!=0`.

Hopefully this helps!