How do you solve $1/m=(m-34)/(2m^2)$ ?

Question

3370 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-12-28T05:45:55

$m=-34$ . See below.

Given $1/m=(m-34)/(2m^2)$ , we can isolate the variable $m$ to determine its value.

Multiply both sides by $(2m^2)$

$=>(2m^2)/m=m-34$

On the left we have $m^2/m^1$ , which, by the rules of exponents, is equivalent to $m^(2-1)=m^1=m$ .

$=>2m=m-34$

Subtract $m$ from both sides

$=>2m-m=-34$

$=>m=-34$

Check your answer by plugging in $-34$ for $m$ and verifying that the expression is true:

$1/(-34)=(-34-34)/(2*(-34)^2$

$=>-1/(34)=(-68)/(2312)$

Simplify the fraction on the right by dividing numerator and denominator by $68$

$=>-1/(34)=-1/(34)$

Our answer is correct.

How do you solve 1/m=(m-34)/(2m^2)1/m=(m-34)/(2m^2)?