How do you solve #1/m=(m-34)/(2m^2)#?

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Answer 1 · 2016-12-28T05:45:55

#m=-34#. See below.

Given #1/m=(m-34)/(2m^2)#, we can isolate the variable #m# to determine its value.

Multiply both sides by #(2m^2)#

#=>(2m^2)/m=m-34#

On the left we have #m^2/m^1#, which, by the rules of exponents, is equivalent to #m^(2-1)=m^1=m#.

#=>2m=m-34#

Subtract #m# from both sides

#=>2m-m=-34#

#=>m=-34#

Check your answer by plugging in #-34# for #m# and verifying that the expression is true:

#1/(-34)=(-34-34)/(2*(-34)^2#

#=>-1/(34)=(-68)/(2312)#

Simplify the fraction on the right by dividing numerator and denominator by #68#

#=>-1/(34)=-1/(34)#

Our answer is correct.