How do you solve #1/x+1>=0# using a sign chart?

1 Answer
Shwetank Mauria
Sep 9, 2017

Solution is #x<=-1# or #x>=0# and in interval form it is #{x in(-oo,-1]uu[0,oo)}#

Explanation:

We can write #1/x+1>=0# as #(1+x)/x>=0#

Hence, for inequality ti satisfy,

we should have sign of both #1+x# and #x# same i.e.

#1+x>=0# and #x>=0# i.e. #x>=-1# and #x>=0# i.e. #x>=0#

or #1+x<=0# and #x<=0# i.e. #x<=-1# and #x<=0# i.e. #x<=-1#

Hence solution is #x<=-1# or #x>=0# and in interval form it is #{x in(-oo,-1]uu[0,oo)}#

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