How do you solve #10/(3x)-8=2/x# and find any extraneous solutions?
1 Answer
Jul 9, 2016
#x=1/6#
Explanation:
#10/(3x)-8=2/x# Multiply both sides by#x#
#(10x)/(3x)-8x=2#
#(10 cancelx)/(3 cancelx)-8x=2# Multiply both sides by#3#
#(10xx3)/3-((8x)xx3)=2xx3#
#(10xxcancel3)/cancel3-24x=6#
#10-24x=6#
#-24x=6-10=-4#
#x=(-4)/(-24)=1/6#
