How do you solve #-10x-8=2x#?

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Answer 1 · 2018-03-25T02:48:45

#x=-2/3#

Solve:

#-10x-8=2x#

Add #10x# to both sides.

#-10x+10x-8=2x+10x#

Simplify.

#0-8=12x#

#-8=12x#

Divide both sides by #12#.

#(-8)/12=(color(red)cancel(color(black)(12x))^1)/color(red)cancel(color(black)(12))^1#

Simplify.

#-8/12=x#

Reduce the fraction by dividing both the numerator and denominator by #4#.

#-(8-:4)/(12-:4)=x#

Simplify.

#-2/3=x#

Switch sides.

#x=-2/3#