How do you solve $- 116 = - 4 + 7 (x - 8)$ $-116= - 4+ 7( x - 8)$ ?

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Answer 1 · 2018-03-10T04:35:11

$x = - 8$ $x=-8$

$- 116 = - 4 + 7 (x - 8)$ $-116 = -4+7(x-8)$

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$- 116 = - 4 + 7 (x) + (7) (- 8)$ $-116=-4 + 7(x)+(7)(-8)$

$- 116 = - 4 + 7 x - 56$ $-116=-4+7x -56$

$- 116 = 7 x - 60$ $-116 = 7x - 60$

Now we need to flip the equation

$7 x - 60 = - 116$ $7x - 60 = -116$

Add $60$ $60$ on both sides

$7 x - 60 + 60 = - 116 + 60$ $7x - 60 + 60 = -116 + 60$

$7 x = - 56$ $7x = -56$

Divide both sides by $7$ $7$

$\frac{7 x}{7} = \frac{- 56}{7}$ $(7x)/7 = (-56)/7$

$x = - 8$ $x=-8$

How do you solve -116= - 4+ 7( x - 8)−116=−4+7(x−8)-116= - 4+ 7( x - 8)?