How do you solve #(-11x+5)/ 6=-1/2#?

1 Answer
Mar 3, 2018

#x=8/11#

Explanation:

#(-11x+5)/6=-1/2#

#(-11x+5)/6color(blue)(*6)=-1/2color(blue)(*6)#

#(-11x+5)/color(red)cancelcolor(black)6*color(red)cancelcolor(black)6=-1/2*6#

#-11x+5=-6/2#

#-11x+5=-3#

#-11x+5color(blue)(-5)=-3color(blue)(-5)#

#-11xcolor(red)cancel(color(black)(+5-5))=-3-5#

#-11x=-8#

#(-11x)/color(blue)(-11)=(-8)/color(blue)(-11)#

#(color(red)cancel(color(black)(-11))x)/color(red)cancel(color(black)(-11))=(-8)/(-11)#

#x=8/11#

That is the answer. We can make sure that it is correct by plugging it into the original equation:

#color(white)=>(-11x+5)/6=-1/2#

#=>(-11(8/11)+5)/6=-1/2#

#color(white)=>(-color(red)cancelcolor(black)11(8/color(red)cancelcolor(black)11)+5)/6=-1/2#

#(-8+5)/6=-1/2#

#(-3)/6=-1/2#

#-1/2=-1/2 qquadcolor(lightgreen)sqrt#

Since this statement is true, our answer is correct.