How do you solve #12x^2 + 2x = 0#?
1 Answer
Explanation:
You can solve this quadratic by factoring it to the form
The product of two distinct terms is equal to zero if either one of those terms is equal to zero, so you have
#2x = 0# or#(6x+1) = 0#
The solutions to these equations are
and
Alternatively, you could use the general quadratic form
#color(blue)(ax^2 + bx + c = 0)#
and recognize that
#color(blue)(x_(1,2) = (-b +- sqrt(b^2 - 4ac))/(2a)#
is reduced to
#x_(1,2) = (-b +- sqrt(b^2 + 4 * a * 0))/(2a) = (-b +- b)/(2a)#
In your case,