How do you solve $12 x - 4 = 32$ $12x-4=32$ ?

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Answer 1 · 2017-06-14T18:33:55

$x = 3$ $x=3$

First, add four to both sides which will leave you with

$12 x = 36$ $12x=36$

Next, divide by $12$ $12$ on both sides leaving you with

$x = 3$ $x=3$

Answer 2 · 2017-06-14T18:34:53

See a solution process below:

Step 1) Add $4$ $color(red)(4)$ to each side of the equation to isolate the $x$ $x$ term while keeping the equation balanced:

$12 x - 4 + 4 = 32 + 4$ $12x - 4 + color(red)(4) = 32 + color(red)(4)$

$12 x - 0 = 36$ $12x - 0 = 36$

$12 x = 36$ $12x = 36$

Step 2) Divide each side of the equation by $12$ $color(red)(12)$ to solve for $x$ $x$ while keeping the equation balanced:

$\frac{12 x}{12} = \frac{36}{12}$ $(12x)/color(red)(12) = 36/color(red)(12)$

$(color(red)(cancel(color(black)(12)))x)/cancel(color(red)(12)) = 3$

$x = 3$

How do you solve 12x-4=3212x−4=3212x-4=32?