Question

How do you solve `13= \frac { 4- b } { 3}`?

Answer 1

`b = -35`

Explanation:

As per the question, we have

`13 = (4 - b)/3`

`13` x `3 = (4 - b)/3` x `3` ... [Multiplying 3 on both the sides]

`:.39 = (4 - b)/cancel3` x `cancel3`

`:. 39 = 4 - b`

`:.39 - 4 = 4 - 4 - b` ... [Subtracting 4 from both the sides]

`:.35 = cancel4 cancel-4 - b`

`:. - b = 35`

`:. b = -35`

Hence, the answer.

Answer 2

`b=-35`

Explanation:

`"multiply both sides by 3"`

`3xx13=cancel(3)xx(4-b)/cancel(3)`

`39=4-b`

`"subtract 4 from both sides"`

`39-4=cancel(4)cancel(-4)-b`

`35=-b" or "b=-35`

`color(blue)"As a check"`

Substitute this value into the right side of the equation and if equal to the left side then it is the solution.

`(4-(-35))/3=(4+35)/3=39/3=13`

`b=-35" is the solution"`

Answer 3

`b=-35`

Explanation:

Multiply by `3`:

`(13xx3)=(4-b)/cancel3`

`rArr 39=4-b`

Bring the `b` to the other side to make is positive:

`b+39=4`

`rArr b=-35`