How do you solve $16 = 2^{x + 1}$ $16=2^(x+1)$ ?

1 Answer

Oct 3, 2015

I found $x = 3$ $x=3$

Explanation:

Write it as:
$2^{4} = 2^{x + 1}$ $2^4=2^(x+1)$
take ${log}_{2}$ $log_2$ on both sides to get rid of the $2$ $2$ :
$4 = x + 1$ $4=x+1$
$x = 4 - 1 = 3$ $x=4-1=3$

Answer link

Impact of this question

2866 views around the world

You can reuse this answer
Creative Commons License

Science

Math

Humanities

... and beyond

How do you solve $16 = 2^{x + 1}$ $16=2^(x+1)$ ?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you solve 16=2x+116=2^(x+1)?

1 Answer

Explanation:

Related questions

Impact of this question

How do you solve $16 = 2^{x + 1}$ $16=2^(x+1)$ ?