How do you solve #16^(n-7)+5=24#?

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Answer 1 · 2016-09-04T19:30:11

#n = 8.06198#

Isolate the term with the variable.

#16^(n-7) = 19#

19 is clearly not an exact power of 16.
The variable is in the index, so use logs.

#log16^(n-7) = log19#

#(n-7)log16 = log19#

#(n-7) = log19/log16#

#n-7 = 1.06198#

#n = 8.06198#