How do you solve #2^(2x-1) = 8^(x+7)#?

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Answer 1 · 2016-09-04T14:12:13

#x = - 22#

We have: #2^(2 x - 1) = 8^(x + 7)#

Let's express the right-hand side in terms of #2#:

#=> 2^(2 x - 1) = (2^(3))^(x + 7)#

Using the laws of exponents:

#=> 2^(2 x - 1) = 2^(3 x + 21)#

#=> 2 x - 1 = 3 x + 21#

#=> x = - 22#