How do you solve $2/3 = 2 - (5x-3)/(x-1)$ ?

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Answer 1 · 2018-06-25T21:29:52

$x=5/11$

Let's subtract $2$ from both sides to get

$2/3-6/3=-(5x-3)/(x-1)$

$=>-4/3=-(5x-3)/(x-1)$

To get rid of the $x-1$ in the denominator, let's multiply both sides by it. This gives us

$(-4(x-1))/3=-(5x-3)$

We can also get rid of the $3$ in the denominator by multiplying both sides by it. We get

$-4(x-1)=-3(5x-3)$

Let's distribute the $-4$ and $-3$ to their respective terms to get

$-4x+4=-15x+9$

Adding $15x$ on both sides gives us

$11x+4=9$

Subtracting $4$ from both sides, we get

$11x=5$

Lastly, dividing both sides by $11$ gives us

$x=5/11$

Hope this helps!

How do you solve 2/3 = 2 - (5x-3)/(x-1) 2/3 = 2 - (5x-3)/(x-1)?