How do you solve # 2/3 = 2 - (5x-3)/(x-1)#? Algebra Rational Equations and Functions Clearing Denominators in Rational Equations 1 Answer G_Ozdilek Mar 20, 2018 Arrange the equation and get #x=5/11# Explanation: #2/3 = {2(x-1) - 5x-3}/(x-1)# #2(x-1) = 3{2(x-1) - (5x-3)}# #2x - 2 = 3{2x - 5x -2 +3}# #2x - 2 = -9x +3# #2x + 9 x = 3+2# #11x = 5# #x=5/11# Answer link Related questions What is Clearing Denominators in Rational Equations? How do you solve rational expressions by multiplying by the least common multiple? How do you solve #5x-\frac{1}{x}=4#? How do you solve #-3 + \frac{1}{x+1}=\frac{2}{x}# by finding the least common multiple? What is the least common multiple for #\frac{x}{x-2}+\frac{x}{x+3}=\frac{1}{x^2+x-6}# and how do... How do you solve #\frac{x}{x^2-36}+\frac{1}{x-6}=\frac{1}{x+6}#? How do you solve by clearing the denominator of #3/x+2/x^2=4#? How do you solve #2/(x^2+2x+1)-3/(x+1)=4#? How do you solve equations with rational expressions #1/x+2/x=10#? How do you solve for y in #(y+5)/ 2 - y/3 =1#? See all questions in Clearing Denominators in Rational Equations Impact of this question 1119 views around the world You can reuse this answer Creative Commons License