How do you solve 23(3x5)12(4x+3)=14(2x1)112?

1 Answer
Nov 6, 2015

x=9

Explanation:

The first step in this situation is to distribute all values outside of parenthesis

23(3x)=2x
23(5)=103

(The subtraction here is distributed as a negative)

12(4x)=2x
12(3)=32

14(2x)=12x
14(1)=14

This leaves us with:

2x1032x32=12x14112

Combine all like terms (like terms have the same variables attached) (There is a lot of fractional addition but I'm assuming you can calculate those yourself c: )

296=12x13

Add 13 to both sides

296+13=12x13+13

276=12x

Multiply both sides by 2

2762=12x2

273=x

Simplify

x=9

You can check your answer by substituting this value for x in the equation (you need to distribute to solve anyway so I won't repeat that step)
2(9)1032(9)32=12(9)14112

Simplify
18103+1832=9214112

296=194112

296=5812

296=296

Our answer is correct!