How do you solve #2/3 y - 6 = 2#?

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Answer 1 · 2015-10-29T08:31:13

The answer is #y=12#.

#2/3y-6=2#

Simplify #2/3y# to #(2y)/3#.

Add #6# to both sides.

#(2y)/3=2+6=#

#(2y)/3=8#

Multiply both sides times #3#.

#(2y)/(cancel 3)*cancel 3=8*3=#

#2y=24#

Divide both sides by #2#.

#y=24/2=#

#y=12#