How do you solve #2/3e^(4x)+1/3=4#?

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Answer 1 · 2016-08-07T04:42:45

Let's start by isolating the #e^(4x)#.

#2/3e^(4x) = 4 - 1/3#

#2/3e^(4x) = 11/3#

#e^(4x) = (11/3)/(2/3)#

#e^(4x) = 11/2#

#ln(e^(4x)) = ln(11/2)#

#4x(ln(e)) = ln(11/2)#

#4x = ln(11/2)#

#x = 1/4ln(11/2)#

Hopefully this helps!