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How do you solve $2 (3 r + 1) = 2 r$ $2(3r + 1) = 2r$ ?

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Jun 25, 2015

$2 (3 r + 1) = 2 r$ $2(3r+1)=2r$

Distribute the $2$ $2$ on the left side of the inequality.

$6 r + 2 = 2 r$ $6r+2=2r$

Subtract $2$ $2$ from both sides.

$6 r = 2 r - 2$ $6r=2r-2$

Subtract 2r from both sides.

$4 r = - 2$ $4r=-2$

Divide both sides by $4$ $4$ .

$r = \frac{- 2}{4}$ $r=(-2)/(4)$

$r = - \frac{1}{2}$ $r=-1 /2$

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