How do you solve #2(3r + 1) = 2r#?

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Answer 1 · 2015-06-25T06:54:28

#2(3r+1)=2r#

Distribute the #2# on the left side of the inequality.

#6r+2=2r#

Subtract #2# from both sides.

#6r=2r-2#

Subtract 2r from both sides.

#4r=-2#

Divide both sides by #4#.

#r=(-2)/(4)#

#r=-1 /2#