Question

How do you solve `2/3t< -48`?

Answer 1

See the entire solution process below:

Explanation:

Multiply each side of the inequality by `color(red)(3)/color(blue)(2)` to solve for `t` while keeping the inequality balanced:

`color(red)(3)/color(blue)(2) xx 2/3t < color(red)(3)/color(blue)(2) xx -48`

`cancel(color(red)(3))/cancel(color(blue)(2)) xx color(blue)(cancel(color(black)(2)))/color(red)(cancel(color(black)(3)))t < color(red)(3)/color(blue)(2) xx -(2 xx 24)`

`t < color(red)(3)/cancel(color(blue)(2)) xx -(color(blue)(cancel(color(black)(2))) xx 24)`

`t < 3 xx -24`

`t < -72`