How do you solve $\frac{2}{3} x - \frac{2}{3} = 0$ $2/3x-2/3=0$ ?

Question

1958 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-07-08T09:22:19

$x = 1$ $color(blue)(x=1$

$(\frac{2}{3}) x - (\frac{2}{3}) = 0$ $(2/3)x - (2/3) = 0$

$\frac{2 x - 2}{3} = 0$ $(2x - 2)/3 = 0$

$2 x - 2 = 0 \times 3$ $2x - 2 = 0 xx 3$

$2 x - 2 = 0$ $2x - 2 = 0$

$2 x = 2$ $2x = 2$

$x = 1$ $color(blue)(x=1$

How do you solve 23x−23=02/3x-2/3=0?