How do you solve $\frac{2}{3} x + \frac{5}{6} = \frac{1}{2} x - \frac{7}{9}$ $2/3x+5/6=1/2x-7/9$ ?

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Answer 1 · 2017-07-24T10:54:45

By some arrangement, you can get $x = - \frac{29}{3}$ $x=-29/3$

Combine terms (xs on the left hand side and numbers on the right hand side, for example):

$\frac{2 x}{3} - \frac{x}{2} = - \frac{7}{9} - \frac{5}{6}$ $(2x)/3 - x/2 = -7/9 - 5/6$

$\frac{4 x - 3 x}{6} = \frac{- 14 - 15}{18}$ $(4x - 3x)/6 = (-14-15)/18$

$\frac{x}{6} = - \frac{29}{18}$ $x/6 = -29/18$

$x = - \frac{29}{3}$ $x= -29/3$

How do you solve 23x+56=12x−792/3x+5/6=1/2x-7/9?