How do you solve 2/(3y-4)=5/(6y-7)23y4=56y7?

1 Answer
Jul 6, 2017

color(magenta)(y=2y=2

Explanation:

2/(3y-4)=5/(6y-7)23y4=56y7

cross multiply

:.2(6y-7=5(3y-4))

:.12y-14=15y-20

:.12y-15y=-20+14

:.-3y=-6

multiply both sides by -1

:.3y=6

:.color(magenta)(y=2
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color(blue)("Check")

substitute color(magenta)(y=2

:.2/(3(color(magenta)2)-4)=5/(6(color(magenta)2)-7)

:.2/(6-4)=5/(12-7)

:.2/2=5/5

:.color(magenta)(1=1