How do you solve #2/(3y-4)=5/(6y-7)#?

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Answer 1 · 2017-07-06T11:19:27

#color(magenta)(y=2#

#2/(3y-4)=5/(6y-7)#

cross multiply

#:.2(6y-7=5(3y-4))#

#:.12y-14=15y-20#

#:.12y-15y=-20+14#

#:.-3y=-6#

multiply both sides by# -1#

#:.3y=6#

#:.color(magenta)(y=2#
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
#color(blue)("Check")#

substitute #color(magenta)(y=2#

#:.2/(3(color(magenta)2)-4)=5/(6(color(magenta)2)-7)#

#:.2/(6-4)=5/(12-7)#

#:.2/2=5/5#

#:.color(magenta)(1=1#