Question

How do you solve `2/7x+12=22`?

Answer 1

`x=35`

Explanation:

`"subtract 12 from both sides of the equation"`

`2/7xcancel(+12)cancel(-12)=22-12`

`rArr2/7x=10`

`"multiply both sides by "7/2`

`cancel(7)/cancel(2)xxcancel(2)/cancel(7)x=7/2xx10`

`rArrx=(7xx10)/2=35`