How do you solve $- 2 = 8 - 2 y$ $-2 = 8 - 2y$ ?

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Answer 1 · 2018-03-26T10:36:15

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$- 2 = 8 - 2 y$ $-2=8-2y$

$- 2 (- 8) = (8) - 8 - 2 y$ $-2(-8)=(8)-8-2y$
(Subtracting 8 from both sides)

$\frac{- 10}{- 2} = \frac{- 2 y}{- 2}$ $(-10)/(-2)=(-2y)/-2$
(divide both sides by -2)

$y = 5$ $y=5$

How do you solve −2=8−2y-2 = 8 - 2y?