How do you solve #2*e^(x-6)=63#? Precalculus Properties of Logarithmic Functions Natural Logs 1 Answer Alan P. Sep 30, 2016 #x=9.45# (to 2 decimal places) Explanation: If #color(white)("XXX")2 * e^(x-6)=63# then #color(white)("XXX")e^(x-6)=63/2=31.5# and #color(white)("XXX")x-6 = ln(31.5) ~~3.45# (using a calculator) #rArr x~~9.45# Answer link Related questions What is the natural log of e? What is the natural log of 2? How do I do natural logs on a TI-83? How do I find the natural log of a fraction? What is the natural log of 1? What is the natural log of infinity? Can I find the natural log of a negative number? How do I find a natural log without a calculator? How do I find the natural log of a given number by using a calculator? How do I do natural logs on a TI-84? See all questions in Natural Logs Impact of this question 1878 views around the world You can reuse this answer Creative Commons License