How do you solve # 2 ln (x + 3) = 0# and find any extraneous solutions?

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Answer 1 · 2016-06-10T05:39:50

This equation means that #x+3=1# or more precisely #x+3= e^(2ipi/n)#. For x real #x + 3 = +-1# thus #x= -4 and x=-2#