How do you solve #2/(x+1) + 5/(x-2)=-2#?

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Answer 1 · 2017-10-29T10:43:11

Solution: #x=1/2 and x=-3#

# 2/(x+1)+5/(x-2) =-2# . Multiplying by #(x+1)(x-2)# on both

sides we get , # 2(x-2)+5(x+1) =-2(x+1)(x-2)# or

#2x-4+5x+5 = -2(x^2-x-2)#or

#7x+1 = -2x^2+2x+4 or 2x^2+5x-3=0# or

#2x^2+6x-x-3=0 or 2x(x+3)-1(x+3)=0# or

#(x+3)(2x-1)=0 #. Either #x+3=0:.x=-3# or

#2x-1=0 :. x= 1/2 #

Solution: #x=1/2 and x=-3# [Ans]