How do you solve #2^(x) + 2^(2x) = 72#? Precalculus Properties of Logarithmic Functions Common Logs 1 Answer Cesareo R. Jun 22, 2016 #x = 3# Explanation: Taking #y = 2^x# we have #y+y^2=72# Solving for #y# we get #{y = -9},{y = 8}# but #y = 2^x# must be positive then we follow with #y = 2^x = 8->x = 3# Answer link Related questions What is the common logarithm of 10? How do I find the common logarithm of a number? What is a common logarithm or common log? What are common mistakes students make with common log? How do I find the common logarithm of 589,000? How do I find the number whose common logarithm is 2.6025? What is the common logarithm of 54.29? What is the value of the common logarithm log 10,000? What is #log_10 10#? How do I work in #log_10# in Excel? See all questions in Common Logs Impact of this question 2475 views around the world You can reuse this answer Creative Commons License