How do you solve #2( y - 6) + 3y = 2( y + 2) - y#?

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Answer 1 · 2018-03-20T10:57:51

#color(magenta)(y=4#

#2(y-6)+3y=2(y+2)-y#

Opening the brackets:

#2y-12+3y=2y+4-y#

Adding 12 on both sides:

#5y-12+12=y+4+12#

#5y=y+16#

Subtracting y from both sides:

#5y-y=y+16-y#

#4y=16#

Dividing both sides by 4:

#y=16/4#

#color(magenta)(y=4#
~Hope this helps! :)