How do you solve $2 (y - 6) + 3 y = 2 (y + 2) - y$ $2( y - 6) + 3y = 2( y + 2) - y$ ?

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Answer 1 · 2018-03-20T10:57:51

$y = 4$ $color(magenta)(y=4$

$2 (y - 6) + 3 y = 2 (y + 2) - y$ $2(y-6)+3y=2(y+2)-y$

Opening the brackets:

$2 y - 12 + 3 y = 2 y + 4 - y$ $2y-12+3y=2y+4-y$

Adding 12 on both sides:

$5 y - 12 + 12 = y + 4 + 12$ $5y-12+12=y+4+12$

$5 y = y + 16$ $5y=y+16$

Subtracting y from both sides:

$5 y - y = y + 16 - y$ $5y-y=y+16-y$

$4 y = 16$ $4y=16$

Dividing both sides by 4:

$y = \frac{16}{4}$ $y=16/4$

$y = 4$ $color(magenta)(y=4$
~Hope this helps! :)

How do you solve 2(y−6)+3y=2(y+2)−y2( y - 6) + 3y = 2( y + 2) - y?