How do you solve #20^(-6n)+6=55#? Precalculus Properties of Logarithmic Functions Natural Logs 1 Answer Anjali G Nov 22, 2016 #n=-1/6log_20(49)# #napprox-.2165# Explanation: #20^(-6n)+6=55# Subtract 6 from each side: #20^(-6n)=49# Rewrite as a log: #log_20(49)=-6n# #n=-1/6log_20(49)# Answer link Related questions What is the natural log of e? What is the natural log of 2? How do I do natural logs on a TI-83? How do I find the natural log of a fraction? What is the natural log of 1? What is the natural log of infinity? Can I find the natural log of a negative number? How do I find a natural log without a calculator? How do I find the natural log of a given number by using a calculator? How do I do natural logs on a TI-84? See all questions in Natural Logs Impact of this question 2730 views around the world You can reuse this answer Creative Commons License