Question

How do you solve `20^(x^2)=70`?

Answer 1

`x=+- 1.1909`

Explanation:

take log of both sides,

`log20^(x^2)=log70`
`x^2log20=log70`
`x^2=log70/log20=1.418182....`
`x=+-1.1909` (4 decimal place)