How do you solve # 25x²=20x+6# using the quadratic formula? Algebra Quadratic Equations and Functions Comparing Methods for Solving Quadratics 1 Answer P dilip_k Apr 29, 2016 #x =(2+sqrt10)/5 and x =(2-sqrt10)/5# Explanation: #25x^2=20x+6# #=>25x^2-20x-6=0# #=>(5x)^2-2.5x.2+2^2-4-6=0# #=>(5x)^2-2.5x.2+2^2=4+6# #=>(5x-2)^2=10# #=>(5x-2)=+-sqrt10# #:. x =(2+sqrt10)/5 and x =(2-sqrt10)/5# Answer link Related questions What are the different methods for solving quadratic equations? What would be the best method to solve #-3x^2+12x+1=0#? How do you solve #-4x^2+4x=9#? What are the two numbers if the product of two consecutive integers is 72? Which method do you use to solve the quadratic equation #81x^2+1=0#? How do you solve #-4x^2+4000x=0#? How do you solve for x in #x^2-6x+4=0#? How do you solve #x^2-6x-16=0# by factoring? How do you solve by factoring and using the principle of zero products #x^2 + 7x + 6 = 0#? How do you solve #x^2=2x#? See all questions in Comparing Methods for Solving Quadratics Impact of this question 1614 views around the world You can reuse this answer Creative Commons License