How do you solve #27^(x+2)=3#? Precalculus Properties of Logarithmic Functions Logarithm-- Inverse of an Exponential Function 1 Answer Noah G May 20, 2016 Put in equal bases. Explanation: #(3^3)^(x + 2) = 3# #3^(3x + 6) = 3^1# #3^(3x) = 3^(1 - 6)# #3^(3x) = 3^(-5)# #x = -5/3# Hopefully this helps! Answer link Related questions What is a logarithm? What are common mistakes students make with logarithms? How can a logarithmic equation be solved by graphing? How can I calculate a logarithm without a calculator? How can logarithms be used to solve exponential equations? How do logarithmic functions work? What is the logarithm of a negative number? What is the logarithm of zero? How do I find the logarithm #log_(1/4) 1/64#? How do I find the logarithm #log_(2/3)(8/27)#? See all questions in Logarithm-- Inverse of an Exponential Function Impact of this question 1133 views around the world You can reuse this answer Creative Commons License