How do you solve #(2b - 3)/7 - b/2 = (b + 3)/14#?

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Answer 1 · 2015-05-15T07:02:39

# (2b -3) / (7) - (b)/2 = (b +3) /(14)#

L.C.M of denominators: 7 , 2 and 14 = 14

# ((2b -3) xx 2) / (7 xx 2) - (b xx 7)/(2 xx 7)= (b +3) /(14)#

# (4b - 6) / 14 - (7b) /(14)= (b +3) /(14)#

# (4b - 6 - 7b) /(cancel14)= (b +3) /(cancel14)#

#-3b - 6 = b +3#
#-3b - b = 3 + 6#
#-4b = 9#

#b = (-9)/(4)#