How do you solve #(2b - 3)/7 - b/2 = (b + 3)/14#? Algebra Rational Equations and Functions Clearing Denominators in Rational Equations 1 Answer Don't Memorise May 15, 2015 # (2b -3) / (7) - (b)/2 = (b +3) /(14)# L.C.M of denominators: 7 , 2 and 14 = 14 # ((2b -3) xx 2) / (7 xx 2) - (b xx 7)/(2 xx 7)= (b +3) /(14)# # (4b - 6) / 14 - (7b) /(14)= (b +3) /(14)# # (4b - 6 - 7b) /(cancel14)= (b +3) /(cancel14)# #-3b - 6 = b +3# #-3b - b = 3 + 6# #-4b = 9# #b = (-9)/(4)# Answer link Related questions What is Clearing Denominators in Rational Equations? How do you solve rational expressions by multiplying by the least common multiple? How do you solve #5x-\frac{1}{x}=4#? How do you solve #-3 + \frac{1}{x+1}=\frac{2}{x}# by finding the least common multiple? What is the least common multiple for #\frac{x}{x-2}+\frac{x}{x+3}=\frac{1}{x^2+x-6}# and how do... How do you solve #\frac{x}{x^2-36}+\frac{1}{x-6}=\frac{1}{x+6}#? How do you solve by clearing the denominator of #3/x+2/x^2=4#? How do you solve #2/(x^2+2x+1)-3/(x+1)=4#? How do you solve equations with rational expressions #1/x+2/x=10#? How do you solve for y in #(y+5)/ 2 - y/3 =1#? See all questions in Clearing Denominators in Rational Equations Impact of this question 2693 views around the world You can reuse this answer Creative Commons License