How do you solve #-2e^(7v+5)-10=-17#?

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Answer 1 · 2018-05-14T12:34:54

Solution : #v ~~ -0.535 #

#-2 e^(7 v+5) -10 = -17# or

#-2 e^(7 v+5) = 10-17# or

# e^(7 v+5) = 7/2# Taking natural log on both sides we get,

# (7 v+5) ln e = (ln 7 - ln 2) ; [ln e =1]#

#:. (7 v+5) ~~ 1.253 ; #

#:. 7 v ~~ 1.253-5 or 7 v ~~ -3.75 ; #

#:. v ~~ -3.75/7 ~~ -0.535 (3dp)#

Solution : #v ~~ -0.535 # [Ans]