Question

How do you solve `2m + 18 >12`?

Answer 1

`color(red)(m) > -3`

Explanation:

First, isolate the `color(red)(m)` term on the left side of the inequality and the constants on the right side of the inequality while keeping he equation balanced:

`2color(red)(m) + 18 - color(blue)(18) > 12 - color(blue)(18)`

`2color(red)(m) + 0 > -6`

`2color(red)(m) > -6`

The next step is to solve for `m` while keeping the inequality balanced:

`(2color(red)(m))/color(blue)(2) > -6/color(blue)(2)`

`(color(blue)(cancel(color(black)(2)))color(red)(m))/cancel(color(blue)(2)) > -3`

`color(red)(m) > -3`