How do you solve #-2r-6+r=3#?
1 Answer
May 6, 2018
Explanation:
#"collect terms in r on left side of equation and numeric"#
#"values on the right side"#
#rArr-r-6=3#
#"add 6 to both sides"#
#-rcancel(-6)cancel(+6)=3+6#
#rArr-r=9#
#"multiply both sides by "-1#
#rArrr=-9#
#color(blue)"As a check"# Substitute this value into the left side of the equation and if equal to the right side then it is the solution.
#(-2xx-9)-6-9=18-15=3#
#rArrr=-9" is the solution"#