Question

How do you solve `2s - 3t = 13` and `2s + 2t = -2`?

Answer 1

The solutions are
`color(blue)(s=2,t=-3`

Explanation:

`color(blue)(2s)−3t=13`....equation `1`
`color(blue)(2s)+2t=−2`.....equation `2`

Solving by elimination

Subtracting equation `1` from `2`

`cancelcolor(blue)(2s)−3t=13`
`cancelcolor(blue)(-2s)-2t=+2`

`-5t=15`
`color(blue)(t=-3`

Finding `s`from equation `2`
`2s−3t=13`
`2s=13+3t`
`2s=13-9`
`color(blue)(s=2`